Consider this reaction: 2 C2H6 + 7
O2 → 4 CO2 + 6 H2O
(a) How many grams of oxygen are required to completely react
with (burn) 100.0 g of ethane?
(b) If 55.0 g of ethane is mixed with 55.0 gram of oxygen, and
the mixture then reacts, how many grams of water will be
formed?
What type of chemical reaction is shown below?
C2H6 + O2 --> CO2
+ H2O
Na + Cl2 --> NaCl
H2O ---> H2 + O2
H2 + LiCl ---> HCl + Li
What is the correct order of coefficients to correctly balance
the equation shown below?
____NH4Cl + ____MgO --->
____(NH4)2O + ____MgCl2
C2H6 + ___ O2 --->
CO2 + H2O
Na + Cl2 ---> ___ NaCl
Solve the following linear equations with constant coefficients,
using characteristic equations and undetermined coefficients as
needed.
y''+4y'-12y=x+e^2x y(0)=1,y'(0)=2
Question 2 options:
For the reaction CH4 + O2 →CO2 + H2OCH4 + O2 →CO2 +
H2O
what are the coefficients for each reactant or product?
a. CH4
b. O2
c. CO2
d. H2O
Question 3 (2 points)
Question 3 options:
For the reaction NaOH + AlCl3 →NaCl + Al(OH)3NaOH +
AlCl3 →NaCl + Al(OH)
what are the coefficients for each reactant or product?
a. NaOH
b. AlCl3
c. NaCl
d. Al(OH)3
Question 4 (2 points)
Question 4 options:
For the reaction H2O2...
Balance the equation
__ C8H10(l) + __
O2(g) --> ___
CO2(g) + ___ H2O(g)
A) 3275 grams ( 1 gallon ) of xylene (
C8H10(l)) are chemically combined
with oxygen (O2(g)) in this chemical
reaction. Calculate the number of moles present in the 3275 grams
of xylene (C8H10(l)).
B) If the number of moles C8H10 calculated
in (A) were burned in this combustion reaction, how many moles of
oxygen (O2(g)) would be required to react with the
xylene?
C) If the number...
Balance the combustion reaction of chrysene (C18H12) at 298K.
C18H12(s)+ O2(g) CO2(g) + H2O(l)
What is the value of ng for the combustion reaction? ng = mol
What is Hcomb of chrysene if Ecomb = -8942.6 kJ/mol?
Hcomb = kJ/mol What is the heat of formation of chrysene? See
Thermodynamic Properties Hf = kJ/mol
Write balanced net ionic equations for the following reactions.
Supply H+ and/or H2O as needed to obtain balance
1) MnO4- + Mn2+ +
OH- --> MnO2(s)
2) HPO32-+ MnO4 -+
OH---> PO43- +
MnO42-
Please explain what you did to balance these equations.