In: Statistics and Probability
The efficieny expert investigating the pit stop completion times
collected information from a sample of n = 50 trial run pit stops
and found the average time taken for these trials is 10.75 secs and
that the times varied by a standard deviation of s = 2.5
secs.
Help the efficiency expert to test whether this shows evidence that
the pit crew are completing the change in less than 12 secs,
testing the hypotheses you selected in the previous question.
Complete the test by filling in the blanks in the
following:
The test statistic has value TS= .
Testing at significance level α = 0.05, the rejection region
is:
(less/greater) than (2 dec
places).
Since the test statistic (is in/is not in) the
rejection region, there (is evidence/is no evidence) to
reject the null hypothesis, H 0.
There (is sufficient/is insufficient) evidence to suggest
that the average time taken for the pit crew to complete the pit
stop, μ, is less than 12 .
Were any assumptions required in order for this
inference to be valid?
a: No - the Central Limit Theorem applies, which states the
sampling distribution is normal for any population
distribution.
b: Yes - the population distribution must be normally
distributed.
Insert your choice (a or b):
The test statistic has value TS= .
Testing at significance level α = 0.05, the rejection region
is:
(less/greater) than (2 dec
places).
Since the test statistic (is in/is not in) the
rejection region, there (is evidence/is no evidence) to
reject the null hypothesis, H 0.
Given,
Hence estimate of population mean is 10.75
Therefore, standard error is 0.3535534
Hence, the distribution is normal and we use z- test.
Test statistics is -3.536
Since, the test statistics is in the rejection region, which is also evident from the above normal plot. Hence, null hypothesis is rejected.