In: Physics
An 8-ton truck is initially going up a 20° ramp with a speed of 90 km/hr. The truck, then, brakes reaching a speed of 36 km/hr after 3 seconds. Assuming constant deceleration determine (a) the magnitude of the braking force, (b) the additional time required for the truck to stop. Neglect air resistance and rolling resistance
Use equation of kinematics to find the required deceleration and use Newton’s law of motion to find the magnitude of force as shown below.
a initial speed Ui = 90km/hr = 25 m/s final " Vf=36km/h = 10m/s VF - Vit at 3) 10mis - 25m/s + 2(35) => a = -5m/s2 1F1 = mfal = (800019)5m/2) = 40000w for this case, Vp =0, Vi=10m/s, a=-5 m/s2 Uf = Vitat gives 0 = 10mis +65m183) t = 2 s
a initial speed Ui = 90km/hr = 25 m/s final " Vf=36km/h = 10m/s VF - Vit at 3) 10mis - 25m/s + 2(35) => a = -5m/s2 1F1 = mfal = (800019)5m/2) = 40000w for this case, Vp =0, Vi=10m/s, a=-5 m/s2 Uf = Vitat gives 0 = 10mis +65m183) t = 2 s