Question

In: Statistics and Probability

Recall again that Rind & Bordia (1996) investigated whether or not drawing a happy face on...

Recall again that Rind & Bordia (1996) investigated whether or not drawing a happy face
on customers’ checks increased the amount of tips received by a waitress at an upscale
restaurant on a university campus. During the lunch hour a waitress drew a happy,
smiling face on the checks of a random half of her customers. The remaining half of the
customers received a check with no drawing (18 points).
The tip percentages for the control group (no happy face) are as follows:
45% 39% 36% 34% 34% 33% 31% 31% 30% 30% 28%
28% 28% 27% 27% 25% 23% 22% 21% 21% 20% 18%
8%
The tip percentages for the experimental group (happy face) are as follows:
72% 65% 47% 44% 41% 40% 34% 33% 33% 30% 29%
28% 27% 27% 25% 24% 24% 23% 22% 21% 21% 17%

This time, you are to perform a “hypothesis test” using the tip data, answering each of
the questions below. For short-answer questions, be brief. However, you must give
enough detail to justify your answers. Single-sentence responses will generally not
suffice, but do not exceed a paragraph for any given answer.

n. What is your decision concerning the null hypothesis? Did you reject or
retain?

Solutions

Expert Solution

Let first sample is for no happy face and second sample is for happy face.

The hypotheses are:

This is one tailed (left) hypothesis.

Enter data in excel.

Click on Data->Data Analysis->t-Test: Two-Sample Assuming Unequal Variances and press enter.

Enter data range of no happy face and happy facein variable 1 and 2 text boxes.

Hypothesized Mean Difference = 0

alpha = 0.05

Click OK.

The output is shown below:

P-value for one tailed test is 0.0649, which is greater than level of significance, 0.05. We cannot reject null hypothesis. Therefore, we will retain null.

We cannot conclude that drawing a happy face on customers’ checks increased the amount of tips received by a waitress at an upscale restaurant on a university campus.


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