In parrots, the gene F encodes feather color where FF parrots have yellow feathers, Ff parrots...

In parrots, the gene F encodes feather color where FF parrots have yellow feathers, Ff parrots have green feathers and ff parrots have blue feathers. They also have a gene, B, for beak size that is located 16 map units away from the F gene. BB and Bb encode for longs beaks and bb encodes for short beaks. When FB/fb parrots are crossed to Fb/fB parrots and there are 750 offspring, how many would have short beaks and green feathers?

Also, how do I find the recombination frequency? Is it 16%?

Expert Solution

Answer-

Out of 750, parrots with short beak and green feathers (Fb/fb) are 137

The explanation is given below:

gladiator answered 2 years ago

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