Question

Do the seven steps for each word problem

Step 1: Establish null and alternate hypotheses

State the null and alternative hypothesis (as a sentence and formula).

Step 2: Calculate the degrees of freedom

Step 3: Calculate t _critical using critical t – table

Step 4: Calculate the Sum of Square deviation (SS_D)

Step 5: Calculate t _obtained

Step 6: Specify the critical value and the obtained value on a t-distribution curve

Step 7: Decision and Conclusion

Write a clear and concise conclusion.

A Pullman local sports store is interested in consumer purchasing likelihood of WSU gear (1=not at all to 7=very much) before and after a win in football. A researcher picks 10 WSU students as the participants of the study. The data are shown below. Use alpha = .01 to see whether a win in football increases consumers’ likelihood of buying WSU gear.

After: 4 5 5 6 5 7 5 6 3 4

Before: 3 5 4 4 5 6 5 4 3 3

A marketing researcher has heard that when kids are anonymous, they'll take more candy. To test this hypothesis, she brings 6 kids into a specially-constructed Halloween Lab with two rooms. Each room is identically decorated and contains a decorated front porch, a front door, and a doorbell. Behind the door is a confederate who will answer the door and offer a bowl of candy. The two rooms differ only in their lighting conditions. One room is light; one room is dark, the latter presumably leading to greater anonymity. She says, ok kids, I want you to go into each room and interact with the person behind the door as you would normally interact during Halloween. Ring the doorbell, say trick or treat, and then take some candy. So, the kids do this and the researcher measures how many pieces of candy they take. The data are shown below. Do kids take more candy under conditions that make them feel anonymous? Use alpha = .10.

Light Room:                  1          2          1          1          2          2

Dark Room:                  2          2          3          4          4          3

Answer 1

Step 1:NULL HYPOTHESIS

ALTERNATIVE HYPOTHESIS HA: (One tailed test)

Step 2: Degrees of freedom= n-1=10-1=9

Step 3: Since it is one tailed test , critical value of t with 9 d.f at 0.01 level of significance is

t critical = -2.82

Step 4: Calculate the Sum of Square deviation (SSD)

Step 5: Calculate t obtained

Step 6: Since it is observed that   t=3.207>tc​=-2.821.

Step 7: Decision and Conclusion: Since it is observed that t=3.207>tc​=-2.821, it is then concluded that the null hypothesis is rejected.It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that population mean μ1 (Before)​ is less than μ2(After)​, at the 0.01 significance level.

Step 1: NULL HYPOTHESIS H0:

ALTERNATIVE HYPOTHESIS HA:

STEP2: D.F= n-1= 6-1=5

Step 3: t critical value for one tailed test is -1.476

Step 4: Calculate the Sum of Square deviation (SSD)

Step 5: Calculate t obtained

Step 6: Specify the critical value tc​=−1.476.

STEP 7: It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that population mean μ1​ is less than μ2​, at the 0.1 significance level.