Question

write a function to determine the square root of a number. The square root of a number can be approximated by repeated calculation using the formula NG = 0.5(LG + N/LG) where NG stands for the next guess and LG stands for the last guess. The loop should repeat until the difference between NG and LG is less than 0.00001. Use an initial guess of 1.0. Write a driver program to test your square root function. I WANT THIS PROGRAM IN PYTHON AND WIT PSEUDOCODE!!! AS SIMPLE AS POSSIBLE!!!!

Answer 1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

Note: Please maintain proper code spacing (indentation), just copy the code part and paste it in your compiler/IDE directly, no modifications required.

#code

PSEUDO-CODE FOR THE METHOD CALCULATING SQUARE ROOT

MODULE square_root(num)
   DECLARE LG=1.0
   DECLARE NG=(LG+(num/LG))/2
   WHILE ABS(LG-NG) >= 0.00001 DO
      LG=NG
      NG=(LG+(num/LG))/2
   END WHILE
   RETURN LG
END MODULE

#PYTHON CODE FOR THIS PROBLEM INCLUDING TESTING

#required method to estimate the square root of num
def square_root(num):
    #initializing 1 as initial guess
    LG=1.0
    #calculating second term from LG
    NG=(LG+(num/LG))/2
    #looping until the difference of prev and next is too small
    #(less than 0.00001)
    #note: use smaller values for more accurate results.
    while abs(LG-NG)>=0.00001:
        #storing current NG value as LG
        LG=NG
        #finding the next term
        NG = 0.5*(LG+ (num / LG))
    #returning the value of LG at the end.
    return LG


#main method for testing
def main():
    #reading a value
    n=float(input("Enter a number: "))
    #displaying square root
    print('Square root is',square_root(n))

#calling main()
main()

#OUTPUT

Enter a number: 5
Square root is 2.2360688956433634