Question

In: Statistics and Probability

An engineer is concerned about the potential loss due to failures of equipment. He obtained the...

An engineer is concerned about the potential loss due to failures of equipment. He obtained the following information regarding the failure events:

There are two possible failure types F1 and F2, which are unrelated;

F1 occurs with 3% in 10 years probability;

F2 occurs with 7% in 15 years probability, and

Associated costs in case of failures for F1 and F2 are $1000 and $400, respectively.

(a) Which failure event (F1 or F2) is more likely to happen during a year of operation?

(b) What is the expected loss due to the failures F1 and F2 in a year?

(c) What is the probability of at least one failure in 5 years?

Solutions

Expert Solution

SOLUTION:

From given data,

An engineer is concerned about the potential loss due to failures of equipment. He obtained the following information regarding the failure events:

There are two possible failure types F1 and F2, which are unrelated;

F1 occurs with 3% in 10 years probability;

F2 occurs with 7% in 15 years probability, and

Associated costs in case of failures for F1 and F2 are $1000 and $400, respectively.

F1 occurs with 3% in 10 years probability;

Therefore , each year F1 occurs with 3/10 = 0.3% probability

F2 occurs with 7% in 15 years probability.

Therefore , each year F2 occurs with 7/15 = 0.4667% probability.

(a) Which failure event (F1 or F2) is more likely to happen during a year of operation?

Failure event F2 is more likely to happen during a year of operation.

(b) What is the expected loss due to the failures F1 and F2 in a year?

The expected loss due to the failures F1 and F2 in a year is

= 1000* (0.3/100) + 400*(0.4667/100)

= 3+ 1.8668

= $ 4.8668

The expected loss due to the failures F1 and F2 in a year is $ 4.8668

(c) What is the probability of at least one failure in 5 years?

P(at least one failure in 5 years) = 1 - P(no failure in 5 years)

P(at least one failure in 5 years) = 1 - (0.997*0.995)5

P(at least one failure in 5 years) = 0.039

Therfore,

3.9% is the probability of at least one failure in 5 years


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