In: Statistics and Probability
For this problem, carry at least four digits after the decimal
in your calculations. Answers may vary slightly due to
rounding.
A random sample of 5000 permanent dwellings on an entire
reservation showed that 1641 were traditional hogans.
(a) Let p be the proportion of all permanent dwellings
on the entire reservation that are traditional hogans. Find a point
estimate for p. (Round your answer to four decimal
places.)
(b) Find a 99% confidence interval for p. (Round your
answer to three decimal places.)
lower limit | |
upper limit |
Give a brief interpretation of the confidence interval.
1% of the confidence intervals created using this method would include the true proportion of traditional hogans.99% of all confidence intervals would include the true proportion of traditional hogans. 1% of all confidence intervals would include the true proportion of traditional hogans.99% of the confidence intervals created using this method would include the true proportion of traditional hogans.
(c) Do you think that np > 5 and nq > 5 are
satisfied for this problem? Explain why this would be an important
consideration.
Yes, the conditions are satisfied. This is important because it allows us to say that p̂ is approximately normal.No, the conditions are not satisfied. This is important because it allows us to say that p̂ is approximately binomial. No, the conditions are not satisfied. This is important because it allows us to say that p̂ is approximately normal.Yes, the conditions are satisfied. This is important because it allows us to say that p̂ is approximately binomial.
Solution :
Given that,
n = 5000
x = 1641
Point estimate = sample proportion = = x / n = 1641/5000=0.3282
1 - = 1-0.3282 =0.6718
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z / 2 * (((( * (1 - )) / n)
= 2.576* (((0.3282*0.6718) /5000 )
E = 0.017
A 99% confidence interval for population proportion p is ,
- E < p < + E
0.3282- 0.017< p <0.3282+ 0.017
0.3112< p < 0.3452
The 99% confidence interval for the population proportion p is : lower limit=0.3112,upper limit= 0.3452