In: Statistics and Probability
In the lecture, we covered the “pooled-testing” problem, namely when you do blood test on large number of people, it is more efficient to pool k people’s blood together to do the test: if this pooled blood sample results in negative, then you know all these k people are negative, if this pooled blood sample results in positive, then you need to re-test each one of them in this group. Therefore, for each group of k people, you either test once or k+1 times. Suppose p is the rate of certain disease, in case p= 0.1, in the class, we did the calculation 0f E(X), where x is the random number of times you need to do the test. For this problem, if P= 0.05 and N=150000, do the calculation of E(X) for k =3, 4, 5, 6, 7, 8, 10, 15, 25, 35, and then determine the best k.
is the rate of certain disease and
The probability that selected people do not have the disease is . So we have to conduct
1 test with probability and
tests with probability .
The number of groups in the test is
So the expected number of test is
The expeceted values for is computed below.
k = 3, 71393.75 k = 4, 65324.06 k = 5, 63932.86 k = 6, 64736.22 k = 7, 66677.98 k = 8, 69236.94 k = 10, 75189.46 k = 15, 90506.32 k = 25, 114391.56 k = 35, 129373.21
The expeceted number of tests is minimum when which the best .