Q. what is the difference between Black-litterman and Stutzer’s 2004 optimisation approach ?
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A helicopter flying over a hard-to-reach area had an accident. The team of recatists know that the area where the plane fell has the form given by f(x,y) = xsiny, the last position given by the plane was in (3,0), they also know that the direction with which the helicopter went was determined by a normal vector to the parabola y = x^2 at the point (1,1). Find the speed with which the helicopter was going in the direction indicated so that the group of rescuers can make an estimate of the location of the aircraft.
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Question 3
a. |
8.0 x 10-2 N.m |
b. |
1.6 x 10-25 N.m |
c. |
3.8 x 10-25 N.m |
d. |
4..0 x 10-2 N.m |
Question 4
a. |
1.6 x 10-25 J |
b. |
8.0 x 10-2 J |
c. |
1.6 x 10-19 J |
d. |
4.0 x 10-2 J |
10 points
Question 5
a. |
(-) 5.48 x 10 -18 J |
b. |
(-) 5.48 x 10 -17 J |
c. |
(-) 4.36 x 10 -18 J |
d. |
(-) 8.72 x 10 -18 J |
10 points
Question 6
a. |
0.18 m3 |
b. |
17.8 m3 |
c. |
-9.9 m3 |
d. |
178 m3 |
Question 7
a. |
1.32 x 10-3 m3 |
b. |
0.28 m3 |
c. |
1.32 m3 |
d. |
36.92 m3 |
10 points
Question 8
a. |
6.1 kPa |
b. |
378.9 kPa |
c. |
61.3 kPa |
d. |
61.3 Pa |
10 points
Question 9
a. |
346 m/s, 1308 m/s |
b. |
346 m/s, 1527 m/s |
c. |
681 m/s, 1247 m/s |
d. |
681 m/s, 1527 m/s |
Question 10
a. |
3346 atm |
b. |
1718 atm |
c. |
2267 atm |
d. |
4756 atm |
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A metal sphere of radius a has a uniform (free) charge density σf on its surface. The permittivity of the dielectric region surrounding the sphere varies as , where r is the radial coordinate.
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Four equally charged particles with charge q are placed at the corners of a square with side length L, as shown in the figure below. A fifth charged particle with charge Q is placed at the center of the square so that the entire system of charges is in static equilibrium. What are the magnitude and sign of the charge Q? (Use any variable or symbol stated above as necessary.) magnitude Q =
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The speed of waves on a string is 97 m/s. If the frequency of standing waves is 485Hz, how far apart are the two adjacent nodes?
Two sig figs and proper units
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Part B: Ballistic Pendulum
The questions n the very bottom is pertaining to a lab over projectile motion and its asking to use equations on the bottom to find velocity. Below are the procedures of the lab and the necessary data to find initial velocity.
Calculate the average value for the vertical distance h the pendulum-ball system has risen after the collision. This is the difference between the height of CM at its highest point and that at its lowest point.
1
Gain in Potential Energy = Loss in Kinetic Energy
Potential Energy at highest point =
Mass M of pendulum: 240 grams Mass m of ball: 64 g
Trials | 1 | 2 | 3 | 4 | Avg |
Angle of CM at its lowest point | 0o | 0o | 0o | 0o | |
Angle of CM at its highest point | 33o | 35o | 40o | 40o | |
Angle (highest - lowest) | 33o | 35o | 40o | 40o | |
Distance L from pivot to CM of pendulum | .285 meters | .284 meters |
Kinetic Energy at lowest point =
Height h from angle and L= ?
Velocity V1 of pendulum as it starts to swing=?
Velocity Vo of ball=?
Calculate the average value for the vertical distance h the pendulum-ball system has risen after the collision. This is the difference between the height of CM at its highest point and that at its lowest point.
Using Energy balance and momentum conservation equations, calculate the initial velocity V0 of the projectile.
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1. Why is the steady state concentration gradient linear in equimolecular counter diffusion?
2. Explain why the dissolution of a crystalline particle in a solution can be speeded up by (a) stirring the solution and (b) by crushing the particle, from a mass transfer perspective.
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1) In 2014 the Rosetta spacecraft, orbiting the comet 67P/Churyumov-Gerasimenko, measured the rotation period of the comet's nucleus at 12.404 h. By the time the Rosetta mission ended in 2016, the period had decreased by 21 min. Find the new rotation period, expressed in hours.
2) In Earth’s current epoch, the length of the day is some 86,400.002 ss.
If that were to increase to 86,400.0108 ss, how would you report the increase?
Express your answer with the appropriate units.
3) Add 3.13105 mm and 2.23103 kmkm .
Express your answer with the appropriate units.
4) Add 1.46 mm and 2.3 cmcm.
Express your answer in meters.
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An object moves with constant acceleration 4.10 m/s2 and over a time interval reaches a final velocity of 13.8 m/s.
(a) If its original velocity is 6.90 m/s, what is its
displacement during the time interval?
m
(b) What is the distance it travels during this interval?
m
(c) If its initial velocity is
−6.90 m/s,
what is its displacement during this interval?
m
(d) What is the total distance it travels during the interval in
part (c)?
m
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Two grapes are given equal charges and held apart at a distance of 1.5 m. They experience a repulsive force of 2.2 N. Find the magnitude of the charge on each grape. |
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The weight of your 1430 kg car is supported equally by its four tires, each inflated to a gauge pressure of 33.0 lb/in2 |
Part A: What is the area of contact each tire makes with the road?
Part B: If the gauge pressure is increased, does the area of contact increase, decrease, or stay the same?
Part C: What gauge pressure is required to give an area of contact of 111 cm2cm2 for each tire?
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