Questions
Ball Collision. A ball with a mass of 0.600 kg is initially at rest. It is...

Ball Collision. A ball with a mass of 0.600 kg is initially at rest. It is struck by a second ball having a mass of 0.400 kg, initially moving with a velocity of 0.250 m/s toward the right along the x-axis. After the collision, the 0.400 kg ball has a velocity of 0.200 m/s at an angle of 36.9° above the x axis in the first quadrant. Both balls move on a frictionless, horizontal surface. Find the magnitude of the velocity of the 0.600 kg ball after the collision. Find the direction of the velocity of the 0.600 kg ball after the collision. Find the change in total kinetic energy of the 0.400 kg ball that occurs as a result of the collision. Find the change in total kinetic energy of the 0.600 kg ball that occurs as a result of the collision.

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1.The space shuttle is in a 250-km-high circular orbit. It needs to reach a 610-km-high circular...

1.The space shuttle is in a 250-km-high circular orbit. It needs to reach a 610-km-high circular orbit to catch the Hubble Space Telescope for repairs. The shuttle

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Question 1- In a bizarre way to test the speed of a clay ball shot from...

Question 1-

In a bizarre way to test the speed of a clay ball shot from a slingshot, a wooden block is set up outside the lab on the concrete. The sticky clay ball has a mass of 10.0 g and is hurled perfectly horizontally by a man with his slingshot at a 90 g wooden block initially at rest on the concrete, a compete horizontal surface. The clay sticks to the block. After impact, the block slides 7.50 m before coming to rest. If the coefficient of friction between block and surface is 0.650, what was the speed of the clay (in m/s) immediately before impact?

m/s

Question 2-

In the sport of speed skating, the top athletes experience centripetal acceleration of approximately 0.65 g (meaning the centripetal force is about 65% of their weight). If the radius of the inner lane is about 22.6 meters, how fast are the skaters going?

m/s

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Explain the following causes of color: a. Why are rubies red? They are basically single crystals...

Explain the following causes of color:

a. Why are rubies red? They are basically single crystals of Al2O3 with 1% of Cr impurities. Bulk Al2O3 has a band gap of 8.8 eV.

b. Contrast the different causes of color in chlorophyll, in Si and in the gemstone Al2O3.

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Light from a helium-neon laser (?=633nm) is used to illuminate two narrow slits. The interference pattern...

Light from a helium-neon laser (?=633nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 3.1mbehind the slits. Thirteen bright fringes are seen, spanning a distance of 50mm .

What is the spacing (in mm) between the slits?

Express your answer using two significant figures

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1. A 25 kg box is lifted upward at a constant rate of 2 m/s. If...

1. A 25 kg box is lifted upward at a constant rate of 2 m/s. If the box is lifted a height of 4 m, how much work is done on the box?

2. A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by pulling on the string?

3.

A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by gravity?

4.

A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by friction?

4.

A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by friction?

4.

A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by friction?

A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by friction?

A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by friction?

A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by friction?

4. A 120 kg box is attached to a string and pulled along a rough, flat surface with a coefficient of friction 0.22. If the string pulls with a force of 500 N and is attached at an angle of 30 degrees above the horizontal, and the box moves strictly horizontally a distance of 5 m.

How much work is done on the box by friction?

5. In  the previous problem concerning the work done by friction. The work done by friction would be negative as it is removing energy from the system and working to slow the motion. True or False?

6. In the previous problems, the Normal force opposes gravity and prevents the object from falling through the surface it is sliding across. The work done by the normal force in this case is negative as it is stopping the motion in the vertical direction. True or False?

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1) What is the current through and voltage across a capacitor after it is fully charged...

1) What is the current through and voltage across a capacitor after it is fully charged in a DC circuit?

a) I=0, V=0

b) I=0, V=max

c) I=max, V=0

d) I=max, V=max

2) What is the current through and voltage across a capacitor after it is fully discharged?

a) I=0, V=0

b) I=0, V=max

c) I=max, V=0

d) I=max, V=max

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two long parallel transmission lines 40.0 cm apart carry 20.0 A and 71.0 A currents. a)...

two long parallel transmission lines 40.0 cm apart carry 20.0 A and 71.0 A currents.

a) find all locations where the net magnetic field of the two wires is zero if these currents are in tbe same direction.
please enter your answer as a distance from the wire carrying 20.0 A


b) find all locations where the net magnetic field of the two wires is zero if these currents are in opposite directions.
please enter answer as two distances the first distance from the wire carrying 20.0 A, and the second distance from the wire carrying 71.0 A

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An object with mass m = 0.6 kg is dropped from the top of the building...

An object with mass m = 0.6 kg is dropped from the top of the building and falls 21 m down in front of the cafe.

1.1 Calculate the speed of the object as it hits the ground and calculate the time for the fall. Neglect in this question the air resistance.

In a more accurate calculation we need to take air resistance into account. In a wind tunnel the air resistance of the object has been measured giving rise to an acceleration of: aair = 0.03v2 where v is the speed of the object.

1.2 Now, taking air resistance into account, find the speed of the object as it hits the ground. Any integrals in your calculation should be calculated by hand!

1.3 Calculate the time of the fall when air resistance is taken into account. (You are allowed to use calculator to calculate occurring integrals when answering this question!)

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Consider the air tracks from lab: A car of mass m is set in motion with...

Consider the air tracks from lab: A car of mass m is set in motion with constant speed. As it moves down the track a mass of 2m is dropped onto the car without causing any damage. The car and additional load continue along the track. How does kinetic energy of the car + load compare to the original kinetic energy of the car?

1) The kinetic energy is 3 times the original kinetic energy

2) The kinetic energy is equal to the original kinetic energy    

3) The kinetic energy is 1/2 times the original kinetic energy

4) The kinetic energy is 1/3 times the original kinetic energy

5) The kinetic energy is 2 times the original kinetic energy

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Question 54 1 pts What happens to a given mass of water as it is cooled...

Question 54 1 pts What happens to a given mass of water as it is cooled from 4°C to zero? it contracts it expands it vaporizes none of the above Flag this Question Question 55 1 pts A gasoline engine operates between a high temperature TH = 127oC a low temperature TC = 27o C. If this engine operates with Carnot efficiency, its efficiency is closest to 10% 25% 33% 79%

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In an EM wave traveling west, the B field oscillates up and down vertically and has...

In an EM wave traveling west, the B field oscillates up and down vertically and has a frequency of 91.0 kHz and an rms strength of 7.15×10−9T. Assume that the wave travels in free space.

Part A: What is the frequency of the electric field? Express your answer to three significant figures and include the appropriate units.

Part B: What is the rms strength of the electric field? Express your answer to three significant figures and include the appropriate units.

Part C: What is the direction of its oscillation?

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To prevent dust and soot particles from polluting the atmosphere, industry often employs static electric charges...

To prevent dust and soot particles from polluting the atmosphere, industry often employs static electric charges in their smokestacks.

Explain the physics principle involved in this application.

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2) The Plank radiation law is I(lambda) = 2 pi h c2/[lambda5 (e hc/labda kT -1)]...

2) The Plank radiation law is

I(lambda) = 2 pi h c2/[lambda5 (e hc/labda kT -1)]

take the derivative of this expression with respect to lambda to show

lambdamax = hc/(4.965kT).

You may uses 5 - x = 5 e-x is true for x = 4.965.

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The charge at a point in space is q (t) = 0.5 cos (6t) C. What...

The charge at a point in space is q (t) = 0.5 cos (6t) C. What is the current at t = −2 s? At an arbitrary time t?

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