In: Statistics and Probability
An automatic machine in a manufacturing process is operating properly if the lengths of an important subcomponent are normally distributed with a mean of 111 cm and a standard deviation of 5.5 cm.
A. Using Excel, find the probability that one selected subcomponent is longer than 113 cm.
Probability =
B. Using Excel, find the probability that if 3 subcomponents are randomly selected, their mean length exceeds 113 cm.
Probability =
Given data,
mean = 111 cm
standard deviation = 5.5 cm
A)
Go to formulas section in menu bar----select more functions -- select NORMDIST enter the values (x=113, mean=111, std deviation=5.5 ,cumulative =1)--press enter
You will get the value of P(x<113)
But we need P(x>113) here which is equal to 1-P(x<113)
= 1-0.641935 = ' 0.358065 ' .
B)
Here ,we will use sample std deviation = 5.5/ sqrt(3) = 5.5/1.732 = 3.17.
by using the same method from above part (a)
as NORMDIST(x=113, mean=111, std deviation=3.17 ,cumulative =1)--- press enter then we get 0.735952
the answer you should get is (1- 0.735952) = '
0.264048 '
.