In: Statistics and Probability
We wish to estimate p to within 0.02 units with 99% confidence, but are unsure on the possible value of p. What value of p yields the largest possible sample size?
Solution :
Given that,
= 0.5
1 -
= 1 - 0.5= 0.5
margin of error = E = % = 0.02
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2
= 0.005
Z/2
= 2.58 ( Using z table )
Sample size = n = (Z/2
/ E)2 *
* (1 -
)
= (2.58 / 0.02)2 * 0.5 * 0.5
Sample size = 4160
CORRECT OPTION BB. p=0.5