Question

In: Chemistry

An unidentified organic compound containing only C, H, and O was subjected to combustion analysis. When...

An unidentified organic compound containing only C, H, and O was subjected to combustion analysis. When 228.4 g of the substance burned in oxygen gas, 627.4 g of carbon dioxide and 171.2 g of water were collected. Determine the mass of carbon in the original sample and the empirical formula. Please also provide an brief explanation for this problem in sentences. Thanks in advance

Solutions

Expert Solution

moles of CO2 = mass / molar mass

                     = 627.4 / 44

                      = 14.26

moles of C = 14.26

mass of C =14.26 x 12 = 171.1 g

mass of C = 171.1 g

moles of H2O = 171.2 / 18 = 9.51

moles of H = 2 x 9.51 = 19.0

mass of H = 19.1 g

mass of O = 228.4 - (19.1 + 171.1) = 38.2 g

moles of O = 38.2 / 16 = 2.39

moles ratio : C:H:O = 14.26 : 19.1 : 2.39

                                = 6 : 8 : 1

empirical formula = C6 H8 O


Related Solutions

A compound containing only C, H and O was subjected to combustion analysis. A sample of...
A compound containing only C, H and O was subjected to combustion analysis. A sample of 9.550×10-2 g produced 1.825×10-1 g of CO2 and 1.120×10-1 g of H2O. Determine the empirical formula of the compound and enter the appropriate subscript after each element. If the molar mass of the compound is 184.276 g/mol, determine the molecular formula of the compound and enter the appropriate subscript after each element.
Combustion of a 0.525g sample of an unknown organic compound containing only C, H, and O...
Combustion of a 0.525g sample of an unknown organic compound containing only C, H, and O yielded 1.113g CO2 and 0.1708g of H20. What is the emperical formula of the compound? If the molar mass of the compound is 166.13g/mol, what is the molecular formula? Please show work!!!!
An organic compound containing C, H, O, and S is subjected to two analytical procedures. In...
An organic compound containing C, H, O, and S is subjected to two analytical procedures. In the first procedure a 9.33 mg sample is burned which gives 19.50 mg of C02 and 3.99 mg of H20. In the second procedure, a separate 11.05 mg sample is fused (melted) with Na202 and the resulting sulfate is precipitated as BaS04, which (when washed and dried) weighs 20.4 mg. (Appropriate amounts of Na202 and a compound containing barium ion are added.) The amount...
0.6908 g of an organic compound containing only C, H, and O was burned in excess...
0.6908 g of an organic compound containing only C, H, and O was burned in excess of pure O2, producing 1.7604 g of CO2 and 0.4504 g of H2O. 6.a) Calculate the number of grams of C and H in the combustion products and therefore in the 0.6908 g of the compound. Also calculate the number of grams of O in the 0.6908 g. Show your work. 6.b) What is the empirical formula of this compound?
A 7.364 gram sample of an organic compound containing only C, H, and O is analyzed...
A 7.364 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 9.343 g CO2 and 2.550 g H2O are produced. In a separate experiment, the molar mass is found to be 104.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound.
Complete combustion of a 4.24 mg sample of a compound containing only C,H, and O atoms...
Complete combustion of a 4.24 mg sample of a compound containing only C,H, and O atoms yields 6.21 mg of carbon dioxide and 2.54 mg of water. What is the empirical formula of the compound ?
When a 0.860 g sample of an organic compound containing C, H, and O was burned...
When a 0.860 g sample of an organic compound containing C, H, and O was burned completely in oxygen, 1.64 g of CO2 and 1.01 g of H2O were produced. What is the empirical formula of the compound?
An organic compound contains C, H, N, and O. Combustion of 0.3069 g of the compound...
An organic compound contains C, H, N, and O. Combustion of 0.3069 g of the compound produces 0.8301 g CO2 and 0.2975 g H2O. A sample of 0.5322 g of the compound was analyzed for nitrogen. At STP, 30.54 mL of dry N2 (g) was obtained. In a third experiment, the density of the compound as a gas was found to be 3.68 g/L at 143 deg C and 244 torr. Calculate the empirical formula and the molecular formula of...
An organic compound contains C, H, N, and O. Combustion of 0.3069 g of the compound...
An organic compound contains C, H, N, and O. Combustion of 0.3069 g of the compound produces 0.8301 g CO2 and 0.2975 g H2O. A sample of 0.5322 g of the compound was analyzed for nitrogen. At STP, 30.54 mL of dry N2 (g) was obtained. In a third experiment, the density of the compound as a gas was found to be 3.68 g/L at 143 deg C and 244 torr. Calculate the empirical formula and the molecular formula of...
An unknown compound contains only C, H, and O. Combustion of 3.50 g of this compound...
An unknown compound contains only C, H, and O. Combustion of 3.50 g of this compound produced 7.96 g of CO2 and 3.26 g of H2O.What is the empirical formula of the unknown compound?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT