In: Statistics and Probability
You wish to test the following claim (HaHa) at a significance
level of α=0.10α=0.10.
Ho:p1=p2Ho:p1=p2
Ha:p1<p2Ha:p1<p2
You obtain a sample from the first population with 153 successes
and 596 failures. You obtain a sample from the second population
with 71 successes and 174 failures. For this test, you should NOT
use the continuity correction, and you should use the normal
distribution as an approximation for the binomial
distribution.
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
The p-value is...
This test statistic leads to a decision to...
As such, the final conclusion is that...
The sample proportions here are computed as:
p1 = 153 / (153+596) = 0.2043
p2 = 71 / (174+71) = 0.2898
The pooled proportion here is computed as:
P = (153+71) / (749+245) = 0.2254
The standard error here is computed as:
The test statistic here is computed as:
Therefore -2.781 is the test statistic value here.
b) As this is a one tailed test, the p-value here is computed form the standard normal tables as:
p = P(Z <- 2.781 ) = 0.0027
Therefore 0.00027 is the p-value here.
Clearly the p-value here is 0.0027 less than 0.10 which is
Therefore the test is significant and
The null hypothesis is rejected here.
#Conclusion
There is not sufficient evidence to warrant rejection of the claim that the first population proportion is less than the second population proportion.
There is not sufficient sample evidence to support the claim that the first population proportion is greater than the second population proportion.