Question

Design and implement a C++ program

• read in a whole line of characters as the input string;
• count and display how many times
• how frequently (among the letters) each (case insensitive) letter appears in the above mentioned input string;

Sample program execution:

An example of executing such a program is shown below. Note that the user input is in italic font.

Please enter a line of characters:
This is a really long line of characters!

There are 41 characters in the input line.
And among them, 33 are letters.

  letter  number   frequency
       A       4    0.121212
       B       0           0
       C       2   0.0606061
       D       0           0
       E       3   0.0909091
       F       1    0.030303
       G       1    0.030303
       H       2   0.0606061
       I       3   0.0909091
       J       0           0
       K       0           0
       L       4    0.121212
       M       0           0
       N       2   0.0606061
       O       2   0.0606061
       P       0           0
       Q       0           0
       R       3   0.0909091
       S       3   0.0909091
       T       2   0.0606061
       U       0           0
       V       0           0
       W       0           0
       X       0           0
       Y       1    0.030303
       Z       0           0

Answer 1

Code:-

#include<iostream>
#include<bits/stdc++.h>
using namespace std;
int main()
{
   cout<<"Enter a string:";
   string str;
   getline(cin, str);
   int n = str.length();
   transform(str.begin(),str.end(),str.begin(),::toupper);
   char ch[n + 1];
   strcpy(ch, str.c_str());
   int letters=0;
   for(int j=0;j<n;j++)
   {
       if(ch[j]>=int('A')&&ch[j]<=int('Z'))
       {
           letters=letters+1;
       }
   }
   cout<<"There are "<<n<<" characters in the input line.\nAnd among them, "<<letters<<" are letters.";
   cout<<"\nletter number frequency"<<endl;
   for(int i=(int)'A';i<=int('Z');i++)
   {
       int count=0;
       char temp;
       for(int j=0;j<n;j++)
       {
           temp=char(i);
           if(ch[j]==temp)
           {
               count=count+1;
           }
       }
       float f=(double)count/letters;
       cout<<temp<<" "<<count<<" "<<f<<endl;
   }
   return 0;
}

Output:-

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