In: Statistics and Probability
9.2
1)
Anyone who has been outdoors on a summer evening has probably heard crickets. Did you know that it is possible to use the cricket as a thermometer? Crickets tend to chirp more frequently as temperatures increase. This phenomenon was studied in detail by George W. Pierce, a physics professor at Harvard. In the following data, x is a random variable representing chirps per second and y is a random variable representing temperature (°F).
x | 19.1 | 16.1 | 19.2 | 18.1 | 17.2 | 15.5 | 14.7 | 17.1 |
y | 90.2 | 72.4 | 93.3 | 85.1 | 82.0 | 75.2 | 69.7 | 82.0 |
x | 15.4 | 16.2 | 15.0 | 17.2 | 16.0 | 17.0 | 14.4 |
y | 69.4 | 83.3 | 79.6 | 82.6 | 80.6 | 83.5 | 76.3 |
Complete parts (a) through (e), given Σx = 248.2, Σy = 1205.2, Σx2 = 4137.66, Σy2 = 97,490.3, Σxy = 20,063.68, and r ≈ 0.856.
(b) Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.)
Σx = | |
Σy = | |
Σx2 = | |
Σy2 = | |
Σxy = | |
r = |
(c) Find x, and y. Then find the equation of the least-squares
line = a + bx. (Round your answers for
x and y to two decimal places. Round your answers for a
and b to three decimal places.)
x | = | |
y | = | |
= | + x |
(e) Find the value of the coefficient of determination
r2. What percentage of the variation in
y can be explained by the corresponding variation
in x and the least-squares line? What percentage is
unexplained? (Round your answer for r2
to three decimal places. Round your answers for the percentages to
one decimal place.)
r2 = | |
explained | % |
unexplained | % |
(f) What is the predicted temperature when x = 19.4 chirps
per second? (Round your answer to two decimal places.)
°F
2)
(a) Suppose you are given the following (x, y) data pairs.
x | 2 | 3 | 5 |
y | 4 | 3 | 9 |
Find the least-squares equation for these data (rounded to three
digits after the decimal).
ŷ = + x
(b) Now suppose you are given these (x, y) data
pairs.
x | 4 | 3 | 9 |
y | 2 | 3 | 5 |
Find the least-squares equation for these data (rounded to three
digits after the decimal).
ŷ = + x
(c) In the data for parts (a) and (b), did we simply exchange the
x and y values of each data pair?
YesNo
(d) Solve your answer from part (a) for x (rounded to
three digits after the decimal).
x = + y
3)
You are the foreman of the Bar-S cattle ranch in Colorado. A neighboring ranch has calves for sale, and you are going to buy some calves to add to the Bar-S herd. How much should a healthy calf weigh? Let x be the age of the calf (in weeks), and let y be the weight of the calf (in kilograms).
x | 3 | 4 | 12 | 16 | 26 | 36 |
y | 42 | 54 | 70 | 100 | 150 | 200 |
Complete parts (a) through (e), given Σx = 97, Σy = 616, Σx2 = 2397, Σy2 = 82,080, Σxy = 13,882, and r ≈ 0.993.
(b) Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.)
Σx = | |
Σy = | |
Σx2 = | |
Σy2 = | |
Σxy = | |
r = |
(c) Find x, and y. Then find the equation of the least-squares
line = a + bx. (Round your answers for
x and y to two decimal places. Round your answers for a
and b to three decimal places.)
x | = | |
y | = | |
= | + x |
(d) Graph the least-squares line. Be sure to plot the point (x, y)
as a point on the line.
(e) Find the value of the coefficient of determination r2. What percentage of the variation in y can be explained by the corresponding variation in x and the least-squares line? What percentage is unexplained? (Round your answer for r2 to three decimal places. Round your answers for the percentages to one decimal place.)
r2 = | |
explained | % |
unexplained | % |
(f) The calves you want to buy are 22 weeks old. What does the
least-squares line predict for a healthy weight? (Round your answer
to two decimal places.)
kg
1) b.
X Values
∑ = 137
Mean = 17.125
∑(X - Mx)2 = SSx = 18.735
Y Values
∑ = 649.9
Mean = 81.238
∑(Y - My)2 = SSy = 489.579
X and Y Combined
N = 8
∑(X - Mx)(Y - My) = 93.382
R Calculation
r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))
r = 93.382 / √((18.735)(489.579)) = 0.975
c.
Sum of X = 137
Sum of Y = 649.9
Mean X = 17.125
Mean Y = 81.2375
Sum of squares (SSX) = 18.735
Sum of products (SP) = 93.3825
Regression Equation = ŷ = bX + a
b = SP/SSX = 93.38/18.74 = 4.984
a = MY - bMX = 81.24 - (4.98*17.13) =
-4.120
ŷ = 4.984X - 4.120
e. Here r=0.975
So r^2=0.975^2=0.951
So explained variation is 95.1%
Unexplained variation is 4.9%
f. for x=19.4, ŷ = (4.984*19.4) - 4.120=92.57