In: Statistics and Probability
The postanesthesia care area (recovery room) at St. Luke’s Hospital in Maumee, Ohio, was recently enlarged. The hope was that the change would increase the mean number of patients served per day to more than 25. A random sample of 15 days revealed the following numbers of patients.
25 | 27 | 25 | 26 | 25 | 28 | 28 | 27 | 24 | 26 | 25 | 29 | 25 | 27 | 24 |
At the 0.01 significance level, can we conclude that the mean number of patients per day is more than 25?
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a. Here claim is that mean is more than 25
vs
Reject the null hypothesis if test-statistic > 2.62
Now sample mean is
Create the following table.
data | data-mean | (data - mean)2 |
25 | -1.0667 | 1.13784889 |
27 | 0.9333 | 0.87104889 |
25 | -1.0667 | 1.13784889 |
26 | -0.066700000000001 | 0.0044488900000001 |
25 | -1.0667 | 1.13784889 |
28 | 1.9333 | 3.73764889 |
28 | 1.9333 | 3.73764889 |
27 | 0.9333 | 0.87104889 |
24 | -2.0667 | 4.27124889 |
26 | -0.066700000000001 | 0.0044488900000001 |
25 | -1.0667 | 1.13784889 |
29 | 2.9333 | 8.60424889 |
25 | -1.0667 | 1.13784889 |
27 | 0.9333 | 0.87104889 |
24 | -2.0667 | 4.27124889 |
Standard deviation is
b. So test statistics is
c. As test statistics is greater than 2.62, we reject the null hypothesis
d. P value is TDIST(2.694,14,1)=0.0087