In: Statistics and Probability
7.) The target temperature for a hot beverage the moment it is dispensed from a vending machine is 173◦F. A sample of 15 randomly selected servings from a newly manufactured vending machine gave a mean temperature of 170◦F with a standard deviation of 6.4◦F. Using our 6-step process, test that the mean tem- perature dispensed from this new machine differs from the target temperature.
Solution:
The null and alternative hypothesis are
H0: = 173 vs Ha: 173
The test statistic t is
t =
= (170 - 173)/(6.4/15)
= -1.815
Now , df = n - 1 = 15 - 1 = 14
Now, sign in H1 indicates that the two tailed test.
Using t = -1.815 , df = 14 , Two tailed test
p value = 0.091
If we use 0.05 significance level , then we fail to reject the null hypothesis. Because the p value is greater than 0.05
There is not sufficient evidence to conclude that the mean tem- perature dispensed from this new machine differs from the target temperature.
If we use 0.10 significance level , then we reject the null hypothesis. Because the p value is less than 0.05
There is sufficient evidence to conclude that the mean tem- perature dispensed from this new machine differs from the target temperature.