In: Chemistry
Using the following balance equation P4 (s) + 6F2 (g) ----> 4PF3 (g)
What mass of F2 is needed to produce 120. g of
PF3 if the reaction has a 78.1% yield?
4*87.96 IGRAMS OG PF3 IS -------------------------------100%
?---------------------------------------------------------78.1%
= 78.1*4*87.96/100
= 274.78 GRAMS
ACCORDING TO THE REACTIO AND THE GIVEN DATA
274.78 GRAMS OF PF3 GIVES BY -------------------------- 6*38 GRMAS OF F2
120 GRAMS OF F2 GIVES BY ---------------------------------------?
= 120*6*38/274.78
=99.50 GRAMS OF F2