Using the following balance equation P4 (s) + 6F2 (g) ----> 4PF3 (g) What mass of...

Using the following balance equation P₄ (s) + 6F₂ (g) ----> 4PF₃ (g)

What mass of F₂ is needed to produce 120. g of PF₃ if the reaction has a 78.1% yield?

Solutions

Expert Solution

4*87.96 IGRAMS OG PF3 IS -------------------------------100%

?---------------------------------------------------------78.1%

= 78.1*4*87.96/100

= 274.78 GRAMS

ACCORDING TO THE REACTIO AND THE GIVEN DATA

274.78 GRAMS OF PF3 GIVES BY -------------------------- 6*38 GRMAS OF F2

120 GRAMS OF F2 GIVES BY ---------------------------------------?

= 120*6*38/274.78

=99.50 GRAMS OF F2

queen_honey_blossom answered 11 months ago

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