In: Accounting
An asset cost $13,000; estimated residual value, $1,000, and estimated life:
Estimated Life |
Actual usage |
|
In years |
5 |
|
In running time (hours) |
3,000 hrs. |
Year 1 = 700 hrs. Year 2 = 3200 hrs. |
In productive output (units) |
10,000 units |
Year 1 = 2000 units Year 2 = 5000 units |
Straight Line
Year |
Depreciation Expense |
Accumulated Depreciation |
Cost |
Net Book Value |
Yr. 1 |
13,000 |
|||
Yr. 1 end |
||||
Yr. 2 |
Service Hours
Year |
Depreciation Expense |
Accumulated Depreciation |
Cost |
Net Book Value |
Yr. 1 |
13,000 |
|||
Yr. 1 end |
||||
Yr. 2 |
Productive Output
Year |
Depreciation Expense |
Accumulated Depreciation |
Cost |
Net Book Value |
Yr. 1 |
13,000 |
|||
Yr. 1 end |
||||
Yr. 2 |
Productive output
Year |
Depreciation Expense |
Accumulated Depreciation |
Cost |
Net Book Value |
Yr. 1 |
13,000 |
|||
Yr. 1 end |
||||
Yr. 2 |
Calculate Depreciation
Straight line
Year | Depreciation Expense | Accumulated Depreciation | Cost | Net Book Value |
Yr. 1 | $ 13,000 | $ 13,000 | ||
Yr. 1 end | $ 2,400 | $ 2,400 | $ 13,000 | $ 10,600 |
Yr. 2 | $ 2,400 | $ 4,800 | $ 13,000 | $ 8,200 |
Service Hours
Depreciation = (Original Value- Salvage Value) / Total Life x
Hours
Year | Depreciation Expense | Accumulated Depreciation | Cost | Net Book Value |
Yr. 1 | $ 13,000 | $ 13,000 | ||
Yr. 1 end | $ 2,800 | $ 2,800 | $ 13,000 | $ 10,200 |
Yr. 2 | $ 9,200 | $ 12,000 | $ 13,000 | $ 1,000 |
Maximum Depreciation is such that Net book value doesnot goes below
Salvage Value
Productivity
Depreciation = (Original Value- Salvage Value) / Total Life x
Units
Year | Depreciation Expense | Accumulated Depreciation | Cost | Net Book Value |
Yr. 1 | $ 13,000 | $ 13,000 | ||
Yr. 1 end | $ 2,400 | $ 2,400 | $ 13,000 | $ 10,600 |
Yr. 2 | $ 6,000 | $ 8,400 | $ 13,000 | $ 4,600 |