There are 15 light bulbs of which 5 are defective. In how many ways can six...

There are 15 light bulbs of which 5 are defective. In how many ways can six light bulbs with exactly one defective be chosen?

C(15,6)

C(10,5)*C(5,1)

P(10,5)*P(5,1)

P(15,6)

How many ways are there to fill out a 25 question multiple choice exam if there are 5 ways to answer each question?

25⁵

5²⁵

C(25,5)

^P(25,5)

How many nonnegative solutions (x_i >=0 for 1<=i<=3) does the equation x₁ + x₂ + x₃ = 10 have?

10³

C(10,3)

C(12,2)

3¹⁰

Solutions

Expert Solution

orchestra answered 11 months ago

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