In: Statistics and Probability
For Problems 1-3, the average annual salary of a Certified Public Accountant (CPA) in one region is $87,000 with a standard deviation of $6300.
3. Suppose that a random sample of 36 CPAs has the same mean as the regional average. Find the probability that the sample mean is less than $85,500.
Solution :
Given that ,
mean =
= $87000
standard deviation =
= $6300
n = 36
= 87000
=
/
n = 6300 /
36=1050
P(
<85500 ) = P[(
-
) /
< (85500-87000) /1050 ]
= P(z <-1.43 )
Using z table
= 0.0764
probability=0.0764