In: Statistics and Probability
Consider the set of five numbers {0, 2, 4, 6, 8}.
1) Make a list of all possible samples of size 2 that can be drawn from this set of integers. (Sample without replacements, that is, once a number is selected, you don’t put it back in the sample set.)
2) Make a list of all possible sample means for samples of size 2 selected from this set.
3) List the distribution of the sample means and construct a histogram of this distribution.
Answer 1 :
List of all possible samples of size 2 -
The samples are drawn using WITHOUT REPLACEMENT procedure . There are a total of 10(= 5C2) different samples of size 2
Answer 2 :
The following table shows the Sample and its mean -
| 
 Sample  | 
 Mean  | 
| 
 (0 , 2)  | 
 1  | 
| 
 (0 , 4)  | 
 2  | 
| 
 (0 , 6)  | 
 3  | 
| 
 (0 , 8)  | 
 4  | 
| 
 (2 , 4)  | 
 3  | 
| 
 (2 , 6)  | 
 4  | 
| 
 (2 , 8)  | 
 5  | 
| 
 (4 , 6)  | 
 5  | 
| 
 (4 , 8)  | 
 6  | 
| 
 (6 , 8)  | 
 7  | 
List of all possible sample means {1 , 2 , 3 , 4 , 5 , 6 , 7}
Answer 3 :
The following table shows the calculations -
| 
 Mean value (xi)  | 
 Probability , P(xi)  | 
 xi P(xi)  | 
 xi2 P(xi)  | 
| 
 1  | 
 1/10 = 0.1  | 
 0.1  | 
 0.1  | 
| 
 2  | 
 1/10 = 0.1  | 
 0.2  | 
 0.4  | 
| 
 3  | 
 2/10 = 0.2  | 
 0.6  | 
 1.8  | 
| 
 4  | 
 2/10 = 0.2  | 
 0.8  | 
 3.2  | 
| 
 5  | 
 2/10 = 0.2  | 
 1.0  | 
 5.0  | 
| 
 6  | 
 1/10 = 0.1  | 
 0.6  | 
 3.6  | 
| 
 7  | 
 1/10 = 0.1  | 
 0.7  | 
 4.9  | 
| 
 Total  | 
 1.0  | 
 4.0  | 
 19  | 
Mean , Expectation of x , E(x) = 
 xi P(xi) = 4.0
E(x2) = 
xi2 P(xi) = 19
Variance of x , Var. (x) = E(x2) - (E(x))2 = 19 - 16 = 3
Standard deviation , S.D. (x) = (Var. (x))1/2 = 1.732
So , the distribution of sample means have mean = 4 and standard deviation = 1.732
The following shows the Histogram -

(where the Horizontal Axis represents the Mean values and the Vertical Axis represents the Probabilities )