In: Statistics and Probability
Required:
Solution :
This is the right tailed test .
The null and alternative hypothesis is
H0 : p = 0.55
Ha : p > 0.55
n =400
x =250
= x / n = 250/400 = 0.62
P0 = 0.55
1 - P0 = 1 -0.55 =0.45
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
=0.62-0.55 / [(0.55*0.45) / 400]
= 3.01
Test statistic = z =3.01
P(z > 3.01 ) = 1 - P(z < 3.01 ) = 1 -0.9987
P-value = 0.0013
= 0.01
P-value <
0.0013 < 0.01
Reject the null hypothesis .
There is sufficient evidence to suggest that