Question

The number of views of a page on a Web site follows a Poisson distribution with a mean of 1.5 per minute.

(i) What is the probability of no views in a minute?

(ii) What is the probability of two or fewer views in 10 minutes?

(iii) What is the probability of two or fewer views in 2 hours?

Answer 1

Solution:

Given: x = the number of views of a page on a Web site follows a Poisson distribution with a mean of 1.5 per minute.

Part i) Find:

P( X = 0) = ............?

Part ii) Find the probability of two or fewer views in 10 minutes

for a minute , mean = 1.5

for 10 minutes, mean = 1.5 X 10 = 15

Thus

Part iii) Find the probability of two or fewer views in 2 hours?

for a minute , mean = 1.5

for 2 houts = 120 minutes, mean = 1.5 X 120 = 180

Thus