In: Chemistry
For a solution of pH of 4.61
What is the [H_3O^+]?
What is the [OH^-]?
What is the pOH?
pH of solution = 4.61
a. We know that, pH = - log [ H3O+]
[ H3O+] = 10-pH
=10-4.61
= 2.455 x 10-5 M
b. We know that, pH + pOH = 14 pOH = 14 - pH = 14 - 4.61 = 9.39
pOH = - log [OH-]
[OH-] = 10-pOH
= 10-9.39
= 4.074 X 10-10 M
c. As calculated above,
pH + pOH = 14
pOH = 14 - pH = 14 - 4.61
pOH = 9.39