In: Statistics and Probability
The success of the Facebook business model depends on users clicking on ads when using the web site. A random sample of 260 Facebook users found that 169 of them click on the ads. Determine the 90% confidence interval for this sample is given by , . (There is a unique answer to this question. Use the z-score from the table. Do not round your answers in the preceding steps. Round the final answers to three decimal places)
Solution :
Given that,
n = 260
x = 169
Point estimate = sample proportion = = x / n = 169/260=0.65
1 - = 1- 0.65 =0.35
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645 ( Using z table )
Margin of error = E Z/2 *(( * (1 - )) / n)
= 1.645 *((0.65*0.35) /260 )
= 0.049
A 90% confidence interval for population proportion p is ,
- E < p < + E
0.65-0.049 < p <0.65+ 0.049
0.601< p < 0.699
The 90% confidence interval for the population proportion p is =0.601, 0.699