Use the method of variation of parameters to find a particular
solution of the given differential equation and then find the
general solution of the ODE.
y'' + y = tan(t)
In Exercises 7–29 use variation of parameters to find a
particular solution, given the solutions y1, y2 of the
complementary equation.
1.) 4xy'' + 2y' + y = sin sqrt(x); y1 = cos sqrt(x), y2 = sin
sqrt(x)
2.) x^2y''− 2xy' + (x^2 + 2)y = x^3 cos x; y1 = x cos
x, y2 = x sinx
Please help!!! with explanation thank you very much only these
two excersices from homework.
Find a general solution to the differential equation using the
method of variation of parameters.
y''+ 25y= sec5t
The general solution is y(t)= ___
y''+9y= csc^2(3t)
The general solution is y(t)= ___