In: Statistics and Probability
first question asked:
Suppose every night I eat a snack. The amount of saturated fat (average fat) is 29 grams with a standard deviation of 4 grams. Find the probability that my saturated fat intake on any given day is below 32 grams. Answer = 0.773
second question:
If I have that same snack every night for the month straight- 31 days - what is the probability that the average daily saturated fat intake is below 32 grams?
Solution :
Given that ,
mean = = 29
standard deviation = = 4
P(X< 32) = P[(X- ) / < (32-29) /4 ]
= P(z <0.75 )
Using z table
=0.7734
probability=0.773
(b)
n = 31
= 29
= / n = 4/ 31=0.7184
P( < 32) = P[( - ) / < (32-29) /0.7184 ]
= P(z < 4.18)
Using z table
= 1
probability=1