In: Chemistry
An environmental chemist working for the Environmental Protection Agency (EPA) was directed to collect razor clams from a heavily-contaminated river superfund site and analyze them for their Cd2 content using graphite furnace atomic absorption spectrometry (GFAAS). The chemist dried the clams at 95° C overnight and ground them in a scientific blender, resulting in approximately 50 g of homogenized dry weight. A representative 69.58 mg sample was taken from the approximately 50 g of dry material and dissolved in 100.0 mL of 0.1 M HCl to create a sample solution. Using the method of standard additions, the chemist prepared five standard solutions in 100.0-mL volumetric flasks, each containing 5.00-mL aliquots of the sample solution. Varying amounts of a 85.0 ppb (μg/L) Cd2 standard were added to each of the flasks, which were then brought to volume with 0.1 M HCl. The Cd2 content of the solutions was then analyzed using GFAAS, resulting in the following absorbance data.
S
| Sample Vol. (mL) | Cd2 Standard Vol. (mL) | Absorbance | 
| 
 5.00  | 
0.00 | 0.080 | 
| 5.00 | 2.50 | 0.119 | 
| 5.00 | 5.00 | 0.163 | 
| 5.00 | 7.50 | 0.200 | 
| 5.00 | 10.00 | 0.241 | 
| 
 Cd2+ conc., originated from std.sol 87 ppb, in 100 mL flasks  | 
 Absorbance (corrected for errors)  | 
 Measured Absorbance – Absorbance in the first flask (without std. additions)  | 
| 
 0 ppb  | 
 0.080  | 
 0.000  | 
| 
 2.17 ppb  | 
 0.120  | 
 0.040  | 
| 
 4.35 ppb  | 
 0.160  | 
 0.080  | 
| 
 6.52 ppb  | 
 0.200  | 
 0.120  | 
| 
 8.70 ppb  | 
 0.240  | 
 0.160  | 
First solve the concentration measurement in the solutions prepared in 100 mL flasks.
The calibration is linear and the slope is
0.160 A.units / 8.70 ppb = 0.0184 a.u/ppb
The absorbance for the unknown itself is 0.080. Then the concentration of the unknown is
0.080 a.u. / 0.0184 a.u/ppb = 4.35 ppb in 100 mL flask (for AAS measurement).
In the 5 mL sample aliquot
Cd2+ conc. = 4.35 ppb x 100 mL/5 mL= 87 ppb = 87 x 10-9 g/mL
In 61 mg sample, the content of Cd2+ is
87 x 10-9 g/mL x 100 mL = 8.70x10-3 mg Cd
61 mg sample (dry clam) contains …….8.70 x10-3 mg Cd
1000 mg (1g)……………………………….x
X = 142.6 x10-3 mg Cd /g dry clam
Rounded result:
0.143 mg Cd /g dry clam