Question

a give the probability of getting a sequence of Gold then Silver then Blue on three consecutive spins. b.If the wheel is spun four times, give the probability of getting Blue only on the fourth spin. c.Give the probability of getting at least one Blue on five consecutive spins. there are 4 red spaces, 2 blue, one gold, and one silver space.

Answer 1

We have a spiinerhaving 4 red spaces, 2 blue, one gold, and one silver space.

Now, let

R: event of getting red in a spin.

B: event of getting blue in a spin.

G: event of getting gold in a spin.

S: event of getting silver in a spin.

a) The probability of getting a sequence of Gold then Silver then Blue on three consecutive spins=

=P(G).P(S).P(B)

b) If the wheel is spun four times,then the probability of getting Blue only on the fourth spin =

=P(not B). P(not B) .P(not B) .P(B)

c) The probability of getting at least one Blue on five consecutive spins=

   = P( getting one blue) + P( getting two blue) + P( getting three blue) + P( getting four blue) + P( getting five blue)