Question

In: Statistics and Probability

A survey of high school students revealed that the numbers of soft drinks consumed per month...

A survey of high school students revealed that the numbers of soft drinks consumed per month was normally distributed with mean 25 and standard deviation 15. A sample of 36 students was selected. What is the probability that the average number of soft drinks consumed per month for the sample was between 28.1 and 30 soft drinks?

Write only a number as your answer. Round to 4 decimal places (for example 0.0048). Do not write as a percentage.

Solutions

Expert Solution

Solution :

Given that,

mean = = 25

standard deviation = = 15

n = 36

=   = 25

= / n = 15 / 36 = 2.5

P(28.1< < 30)  

= P[(28.1 - 25) / 2.5 < ( - ) / < (30 - 25) / 2.5 )]

= P(1.24 < Z < 2)

= P(Z < 2 ) - P(Z < 1.24)

Using z table,  

= 0.9772 - 0.8925

= 0.0847


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