Question
In: Statistics and Probability
A survey of high school students revealed that the numbers of soft drinks consumed per month...
A survey of high school students revealed that the numbers of
soft drinks consumed per month was normally distributed with mean
25 and standard deviation 15. A sample of 36 students was selected.
What is the probability that the average number of soft drinks
consumed per month for the sample was between 26.2 and 30 soft
drinks?
Write only a number as your answer. Round to 4 decimal places (for
example 0.0048). Do not write as a percentage.
Solutions
Expert Solution
Solution :
Given that,
mean = 
= 25
standard deviation = 
= 15
=
/ 
n = 15 /
36 = 2.5
= P[(26.2 - 25) /2.5 < (
-
)
/
< (30 - 25) / 2.5)]
= P( 0.48 < Z < 2)
= P(Z < 2 ) - P(Z < 0.48)
= 0.9772 - 0.6844 = 0.2928 , Probability = 0.2928
orchestra answered 2 years agoRelated Solutions
A survey of high school students revealed that the numbers of soft drinks consumed per month...
A survey of high school students revealed that the numbers of
soft drinks consumed per month was normally distributed with mean
25 and standard deviation 15. A sample of 36 students was selected.
What is the probability that the average number of soft drinks
consumed per month for the sample was between 28.5 and 30 soft
drinks? Write only a number as your answer. Round to 4 decimal
places (for example 0.0048). Do not write as a percentage.
A survey of high school students revealed that the numbers of soft drinks consumed per month...
A survey of high school students revealed that the numbers of
soft drinks consumed per month was normally distributed with mean
25 and standard deviation 15. A sample of 36 students was selected.
What is the probability that the average number of soft drinks
consumed per month for the sample was between 28.1 and 30 soft
drinks?
Write only a number as your answer. Round to 4 decimal places
(for example 0.0048). Do not write as a percentage.
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