In: Chemistry
Le tme begin with a little theoric mark of the bohr model:
According to this, the equation he use to determine the Energy of an atom of Hydrogen is:
En = -Rh x (1/n2) where "n" is the quantum number and corresponds to the different allowed orbits for the electron. Rh is the rydberg constant, and the value for that is -2.18x10-18 J or if you don't want to use this value in J, you can do the conversion by simply multiplying that value for 6.241509 x 1018 eV. If you do that:
Rh = -2.18x10-18 x 6.241509x1018 = -13.6 eV
Now, the four lowest energy levels are (Use the equation 1):
E1 = -13.6 x (1/1) = -13.6 eV
E2 = -13.6 x (1/22) = -3.4 eV
E3 = -13.6 x (1/32) = -1.511 eV
E4 = -13.6 x (1/42) = -0.85 eV
Now, the energies of the photons are calculated for this equation (equation 2)
Eph = Em - En where "m" is an energy level lower than "n".
So for this case, we can actually say that if Hydrogen is in it's ground state then:
Eph1 = E1 - E4 = -13.6 - (-0.85) = -12.75 eV
Eph = E1 - E3 = -13.6 - (-1.511) = -12.089 eV
Eph3 = E1 - E2 = -13.6 - (-3.4) = -10.2 eV
If there is something else you need, or something to add, or to correct, tell me in the comments and I'll add or edit my answer for you.