In: Computer Science
C programing language
write a program to count frequency of each letter, ignore case. Print the letter and frequency of each letter.
// 1A: . Ask the user to enter a password string, store it in pass. Password should contain atleast one Upper case, one Lower case letter , one of the 0-9 digits
(1)
#include<stdio.h>
int main(){
FILE*fptr;
fptr = fopen("data.txt","r");
double sum=0;
int count=0,value;
while(fscanf(fptr, "%d", &value) != EOF){
count++;
sum+=value;
}
printf("Average value : %d\n",sum/value);
fclose(fptr);
return 0;
}
(2)
#include<stdlib.h>
int main(){
char *dt = "The five boxing wizards jump
quickly";
int count[26],i;
for(i=0;i<26;i++)count[i] = 0;
i=0;
while(dt[i] != '\0'){
char ch = dt[i++];
if(ch >= 'A' && ch
<='Z')count[ch-'A']++;
if(ch >= 'a' && ch
<='z')count[ch-'a']++;
}
for(i=0;i<26;i++){
if
(count[i]!=0)printf("%c-%d\n",(i+'a'),count[i]);
}
return 0;
}
(3)
#include<stdio.h>
#include<string.h>
int main(){
char password[25];
int upper,lower,digit,i;
while(1){
upper=0;lower=0;digit=0;
printf("Enter password : ");
scanf("%s",password);
for(i=0;i<strlen(password);i++){
char ch =
password[i];
if(ch>='A'
&& ch<='Z')upper++;
if(ch>='a'
&& ch<='z')lower++;
if(ch>='0'
&& ch<='9')digit++;
}
if(upper>0 && lower>0
&& digit>0)break;
else{
printf("Invalid
password. Re-enter Password\n");
}
}
printf("\nPassword : %s",password);
return 0;
}