In: Statistics and Probability
A sausage company in Sheboygan produces small sausage sandwiches. The company is interested in knowing the average retail price charged for this item in stores across the country. A stats bro that works for the company contacts 36 retailers and find that the average price is $2.13, and the standard deviation is $0.11. Which of the following is the 98% confidence interval around the price.
Group of answer choices:
A)about 2.00≤μ≤2.26
B)about 2.11≤μ≤2.15
C)about 2.05≤μ≤2.21
D)about 2.09≤μ≤2.17
We do not have an adequate table to do this problem
Solution :
Given that,
Point estimate = sample mean = =
=2.13
Population standard deviation =
= 0.11
Sample size = n =36
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02/ 2 = 0.01
Z/2 = Z0.01 = 2.326 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 2.326 * ( 0.11 / 36
)
=0.04
At 98% confidence interval mean
is,
- E <
<
+ E
2.13 - 0.04 <
< 2.13 + 0.04
(2.09 , 2.17)