In: Statistics and Probability
A survey aims to find the proportion of the voting population in favour of a government referendum proposal to abolish the Nexus Rule (between Senate numbers and those in the House of Representatives). They obtain a random sample of 2000 voters to find their opinion and the sample indicates 953 are in favour of the change.
a. (i) State the estimated proportion in favor.
(ii) Find a 95% confidence interval for the proportion in favor. Is the referendum likely to fail?
b. How large a sample would be needed to give an estimate of the population proportion in favor to within ±0.05 with 95% confidence?
Solution:
We are given,
n = 2000
x = 953
a)
i) We have to find estimated proportion in favor ( Sample proportion ):
= x / n = 953 / 2000
= 0.48
ii) We have to Find 95% CI for proportion in favor:
Level of Confidence = 95%
α = 100% - (Level of Confidence) = 5%
α/2 = 2.5% = 0.025
zα/2 = 1.96
Lower Bound = p̂ - zα/2•√p̂(1 - p̂)/n = 0.4581
Upper bound = p̂ + zα/2•√p̂(1 - p̂)/n = 0.5019
Hence Confidence Interval = ( 0.4581 , 0.5019 )
b) We have to find Sample size using formula:
Given, Margin of error = E = 0.05
Keeping all values in formula:
n = 384
Hence we needed 34 sample size.
Done