Question

The school district recently adopted the use of e-textbooks, and the superintendent is interested in determining the level of satisfaction with e-textbooks among students and if there is a relationship between the level of satisfaction and student classification. The superintendent selected a sample of students from one high school and asked them how satisfied they were with the use of e-textbooks. The data that were collected are presented in the following table.

Table 1: Student Classification (N=128)

Satisfied	Freshman	Sophomore	Junior	Senior
Yes	23	21	15	8
No	8	14	15	24

Questions

1. Of the students that were satisfied, what percent were Freshmen, Sophomore, Junior, and Senior? (Round your final answer to 1 decimal place).

2. State an appropriate null hypothesis for this analysis.

3. What is the value of the chi-square statistic?

4. What are the reported degrees of freedom?

5. What is the reported level of significance?

6. Based on the results of the chi-square test of independence, is there an association between e-textbook satisfaction and academic classification?

7. Present the results as they might appear in an article.

This must include a table and narrative statement that reports and interprets the results of the analysis. Note: The table must be created using your word processing program. Tables that are copied and pasted from SPSS are not acceptable.

Answer 1

DATE:17-04-2020.

ANSWER:-------

SECOND_METHOD:

Freshman   Sophomore   Junior   Senior   Total
Yes   23   21       15   8   67
No   8   14       15   24   51

Total   31   35       30   32   118

a) Percent of satisfied from each group:

Freshman= 23/31= 0.741935=74.1935%.

Sophomore= 21/35= 0.6= 60%.

Junior= 15/30= 0.50= 50%.

Senior= 8/32= 0.25= 25%.

2) Chi-square association test:

H0: There is no relationship between student classification and satisfied

Ha: There is relationship between student classification and satisfied

3) Expected value:

E(X)= (Sum of Row * Sum of column)/ Total

E(Freshman* Yes)= (67*31)/128= 16.22656

   Freshman       Sophomore   Junior   Senior       Total
Yes   16.22656       18.32031       15.70313   16.75       67
No   14.77343       16.67968       14.29687   15.25       61  

X^2=SUMMATION(Oi-Ei)**2/Ei.

=16.41291.

4) The degree of freedom: (c-1)(r-1)= (4-1)(2-1)= 3

c= no of columns and r= No of rows

5) Level of significant= 0.05

6) P-value:0.000

The test statistic is significant and rejects H0. There is sufficient evidence to support the claim that there is relationship between student classification and satisfied.