Question

In: Statistics and Probability

An instructor is interested in assessing students' typing speed in the class. He knows that the...

An instructor is interested in assessing students' typing speed in the class. He knows that the average at the university is 49 word per minute (wpm) with a SD of 18 wpm. He collects data from 31 of his students.

a) What is the probability of the average typing speed being less than 49 wpm?
probability =  

b) What is the proability of the average typing speed being between 51 and 53 wpm?
probability =  

Note: Do NOT input probability responses as percentages; e.g., do NOT input 0.9194 as 91.94.

Solutions

Expert Solution

Let x be the students' typing speed in the class.

We are given mean ( µ ) = 49 and standard deviation (σ) = 18 and n = 31

Therefore according to sampling distribution of sample mean , follows approximately normal distribution with mean ()= 49

and standard deviation = = = 3.2329

Part a) P ( < 49 )

=

= P( z < 0 )

= 0.5000 ------ ( from z score table , value for z= 0 )

Part b) P( 51 ≤ ≤ 53 ) = P( ≤ 53 ) - P( ≤ 51 )

=   

= P( z < 1.24 ) - P( z < 0.62 )

= 0.8925 - 0.7324 ------------ ( from z score table )

= 0.1601


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