Question

1) Write an algorithm to calculate the sum of the following series:

Sum =x-x3/3! + x5/5! – x7/7! +……. Stop when the term<0.0001.

2) An internet service provider charges its subscribers per month as follows:

Data usage (n), in gbs charges (NIS)

0.0<n<=1.0 250

1.0<n<=2.0 500

2.0<n<=5.0 1000

5.0<n<=10.0 1500

n>10 2000

Write a C program to read the usage(n) from a file and print the charges to be paid by the subscribers.

Your program must include the function calculate that accept the data usage (n ) and returns the charge/month.

Answer 1

1 ans:

#include <stdio.h>

#include <stdio.h>

#include <math.h>

double fact(int n){

double prd=1;

for(int i=1;i<=n;i++){

prd=prd*i;

}return prd;

}

int main(){

double sum=0;

double term;

double x=3.2;

int cnt=1;

int i=0;

while(1){

term=pow(x,cnt)/fact(cnt);

if(term<0.0001){

break;

}

if(i%2==0){

sum=sum+term;

}else{

sum=sum-term;

}

cnt=cnt+2;

i++;

}

printf("%lf\n",sum);

return 0;

}

2 ans:

#include <stdio.h>

#include <stdlib.h>

int usage(double n){

if(n>=0.0 && n<=1.0){

return 250;

}else if(n>1.0 && n<=2.0){

return 500;

}else if(n>2.0 && n<=5.0){

return 1000;

}else if(n>5.0 && n<=10.0){

return 1500;

}else if(n>=10){

return 2000;

}

}

int main(){

FILE *ptr;

double num;

int filecontentlen=5;

if((ptr=fopen("data.txt","r")) != NULL){

for(int i=0;i<filecontentlen;i++){

fscanf(ptr,"%lf", &num);

int cost=usage(num);

printf("usage=%lf and price=%d\n",num,cost);

}

}else{

printf("Error found!");

}

return 0;

}

#data.txt