In: Statistics and Probability
A population is normally distributed with mean ? and standard deviation ?. Find the percentage of values which are between ?−2? and ?+2?.
Given Mean = ?
Standard Deviation = ?
The formual for Z-score = (X - Mean) / Standard Deviation
Z-score for X = ?−2? is
Z-score = (?−2? - ?) / ?
Z-score = -2
The area to the left of z-score of -2 is calculated by the below attached negative z-table.
The area to the left of z-score of -2 = 0.02275
Z-score for X = ?+2? is
Z-score = (?+2? - ?) / ?
Z-score = 2
The area to the left of z-score of 2 is calculated by the below attached positive z-table.
The area to the left of z-score of 2 = 0.97725
The area between ?−2? and ?+2? = 0.97725 - 0.02275
= 0.954975
So the percentage of values which are between ?−2? and ?+2? = 95.4975%