Question

In: Statistics and Probability

The table below lists the earnings (in thousands of dollars) of a random sample of 12...

The table below lists the earnings (in thousands of dollars) of a random sample of 12 male and 12 female salespersons. At alpha = 0.10 can you conclude that there is a difference between males’ and females’ earnings?

Male

28

43

64

51

48

44

36

45

67

49

40

65

Female

36

27

51

43

35

48

41

37

34

47

50

43

The claim is “there is a difference between males’ and females’ earnings”

Solutions

Expert Solution

1) null and alternate hypothesis

H0:

H1:

2) level of significance = 0.10

3) test statistics

For malw

  N1: 5


df1 = N - 1 = 6 - 1 = 5
M1: 46.33
SS1: 689.33
s21 = SS1/(N - 1) = 689.33/(6-1) = 137.87


For female

N2: 6
df2 = N - 1 = 6 - 1 = 5
M2: 40
SS2: 404
s22 = SS2/(N - 1) = 404/(6-1) = 80.8


T-value Calculation

s2p = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22) = ((5/10) * 137.87) + ((5/10) * 80.8) = 109.33

s2M1 = s2p/N1 = 109.33/6 = 18.22
s2M2 = s2p/N2 = 109.33/6 = 18.22

t = (M1 - M2)/√(s2M1 + s2M2) = 6.33/√36.44 = 1.05

4) p value = 0.3188

5) since p value is greater than level of significance so we fail to reject H0

6) so there insufficient evidence to conclude that there is a difference between males and females earning.


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