In: Statistics and Probability
QUESTION 5 [4]
A courier service company has found that their delivery time of parcels to clients is approximately normally distributed with a mean delivery time of 30 minutes and a variance of 25 minutes (squared).
a) What is the probability that a randomly selected parcel will take between 26 and 42 minutes to deliver? (2)
b) What is the maximum delivery time (minutes) for the 2.5% of parcels with the shortest time to deliver? (2)
Solution: We are given:
a) We are required to find:
Using the z-score formula, we have:
Using the standard normal table, we have:
Therefore, the probability that a randomly selected parcel will take between 26 and 42 minutes to deliver is 0.7799
b) We have to first find the z-value corresponding to area = 0.025. Using the standard normal table, we have:
Now using the z-score formula, we have:
Therefore, the maximum delivery time (minutes) for the 2.5% of parcels with the shortest time to deliver is 20.2 minutes