Question

se technology to find the​ P-value for the hypothesis test described below.

The claim is that for 12 AM body​ temperatures, the mean is

muμgreater than>98.6degrees°F.

The sample size is

nequals=5

and the test statistic is

tequals=1.078.

​P-valueequals=nothing

​(Round to three decimal places as​ needed.)

Answer 1

Solution:

Given:

Claim: For 12 AM body​ temperatures, the mean is μ >98.6 °F.

Since claim is > type this is right tailed test ( one tailed)

n = sample size = 5

thus df = degrees of freedom = n - 1 = 5 - 1 = 4

t = 1.078

We have to find P-value:

Use TI 84 plus calculator to find P-value:

Press 2ND and VARS

Select tcdf(

Enter numbers:

Upper limit is infinity, so enter very large number

click on Paste and press Enter two times

thus

P-value = 0.1708524896

P-value = 0.171

We can use Excel also:

=T.DIST.RT(x,df)

=T.DIST.RT(1.078,4)

=0.17085249

=0.171

Thus P-value = 0.171