Question

In: Statistics and Probability

The table below contains the widths of a product, showing 10 samples of size 5 measurements...

  1. The table below contains the widths of a product, showing 10 samples of size 5 measurements each.

1

2

3

4

5

6

7

8

9

10

40

42

43

41

40

39

45

41

34

42

38

44

46

43

48

48

45

43

43

47

41

40

44

44

43

37

39

40

42

44

43

41

42

43

40

44

46

48

41

42

42

44

40

41

42

39

40

41

42

43

  1. Construct a sample means, X control chart and R chart for the above data.
  2. Identify those subgroup means which are outside the control limits.
  3. Comment on the process.

Solutions

Expert Solution

(i)

We make a table :

Sub-group Number Measurements Total Mean Range
1 40 42 43 41 40 206 41.2 3
2 39 45 41 34 42 201 40.2 11
3 38 44 46 43 48 219 43.8 10
4 48 45 43 43 47 226 45.2 5
5 41 40 44 44 43 212 42.4 4
6 37 39 40 42 44 202 40.4 7
7 43 41 42 43 40 209 41.8 3
8 44 46 48 41 42 221 44.2 7
9 42 44 40 41 42 209 41.8 4
10 39 40 41 42 43 205 41 4
Total N/A N/A 422 58

Hence the mean of the subgroup means and that of the subgroup ranges are given by

Here the subgroup size(n)=5, and therefore from the table of SQC, we have A2=0.577 . Thus,

Then, for the mean chart we have,

Again for the range chart, the values are obtained from the table of SQC for n=5 as

D2 0
D3 2.115

Hence for the range chart,

(ii)

From the control limits of the mean chart, it can be seen that all the subgroup means are within the control limits. Hence there are no subgroup means which are outside the control limits.

Similarly, from the control limits of the range chart, it can be seen that all the subgroup ranges are within the control limits. Hence there are no subgroup ranges which are outside the control limits.

(iii)

As all the subgroup means are within the control limits, it can be concluded that the process is in control. The variations which may still be present in the data are due to chance causes or random causes and cannit be controlled.

Hopefully this will help you. In case of any query, do comment, If you are satisfied with the answer, give it a like. Thanks.


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