In: Statistics and Probability
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting. It is believed that the machine is underfilling the bags. A 39 bag sample had a mean of 441 grams. Assume the population standard deviation is known to be 24. A level of significance of 0.05 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Here, we have to use one sample z test for the population mean.
The null and alternative hypotheses are given as below:
Null hypothesis: H0: the machine is not under filling the bags.
Alternative hypothesis: Ha: the machine is under filling the bags.
H0: µ = 447 versus Ha: µ < 447
This is a lower tailed test.
The test statistic formula is given as below:
Z = (Xbar - µ)/[σ/sqrt(n)]
From given data, we have
µ = 447
Xbar = 441
σ = 24
n = 39
α = 0.05
Critical value = -1.6449
(by using z-table or excel)
Z = (441 – 447)/[24/sqrt(39)]
Z = -1.5612
P-value = 0.0592
(by using Z-table)
P-value > α = 0.05
So, we do not reject the null hypothesis
There is not sufficient evidence to conclude that the machine is under filling the bags.