In: Statistics and Probability
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Conduct a test of hypothesis to determine whether the block of the treatment means differ. Using the .05 significance level:
Treatment |
|||
Block |
1 |
2 |
3 |
A |
12 |
14 |
8 |
B |
9 |
11 |
9 |
C |
7 |
8 |
8 |
PLEASE SHOW ANSWER WITHOUT USING EXCEL OR ANY SOFTWARE. NEED DETAILED WORKINGS OF THE ANSWER. PLEASE NOTE NO EXCEL
a) H0t: There is no significance difference among the
3 treatments
H1t: At least two treatments means are significant
b) Reject H0t f F value > F critical value = 6.9443
c)
H0b: There is no significance difference among the 3
blocks
H1b: At least two blocks means are significant
d) Reject H0b if F value > F critical value = 6.9443
e) From the given data
Treatment | |||||
Block | 1 | 2 | 3 | Ti | Ti^2/3 |
A | 12 | 14 | 8 | 34 | 385.3333 |
B | 9 | 11 | 9 | 29 | 280.3333 |
C | 7 | 8 | 8 | 23 | 176.3333 |
Tj | 28 | 33 | 25 | 86 | 842 |
Tj^2/3 | 261.3333 | 363 | 208.3333 | 832.6667 |
Using above table,
f) Anova Table:
g) Since F value < F critical value of Row (Block) so we accept H0b
Thus we conclude that There is no significance difference among the 3 blocks
Since F value < F critical value of Column (Treatment) so we accept H0t
Thus we conclude that There is no significance difference among the 3 treatments