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At 25 °C and 785 Torr, carbon dioxide has a solubility of 0.0351 M in water....

At 25 °C and 785 Torr, carbon dioxide has a solubility of 0.0351 M in water. What is its solubility at 25 °C and 2030 Torr?

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Expert Solution

   = CRT

/CT   = R

initial                                                           final

T1   = 25+273 = 298K                                T2 = 25+273 = 298K

1   = 785 torr                                              2 = 2030 torr

C1   = 0.0351M                                            C2 =

           1/C1T1 = 2/C2T2

            C2           =    2C1T1/T21

                              = 2030*0.0351*298/298*785    = 0.0907M >>>>>answer

queen_honey_blossom answered 3 years ago
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