In: Chemistry
At 25 °C and 785 Torr, carbon dioxide has a solubility of 0.0351 M in water. What is its solubility at 25 °C and 2030 Torr?
= CRT
/CT = R
initial final
T1 = 25+273 = 298K T2 = 25+273 = 298K
1 = 785 torr 2 = 2030 torr
C1 = 0.0351M C2 =
1/C1T1 = 2/C2T2
C2 = 2C1T1/T21
= 2030*0.0351*298/298*785 = 0.0907M >>>>>answer